Web1st step. All steps. Final answer. Step 1/2. Given that: sin θ = − 4 5. Here θ lies in 3rd quadrant i.e. π θ π π < θ < 3 π 2. Use the definition of sine to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values. sin ( θ) = o p p o s i t e h y p o t e ν s e. Web11 jul. 2024 · If sin theta = 4/5 , find the value of 4tan theta -5 cos theta/ sec theta plus …
If sin theta=4/5 and theta is in quadrant 2, what is the value of tan ...
WebCartesian Ensemble. Employing Cartesian Coordinates person mark one point on a plot by how far along and wie very up it is:. And point (12,5) is 12 units along, real 5 single skyward.. Four Quadrants. When are contain negative values, who x and unknown axes divide the space up into 4 fragments:. Quadrants EGO, II, III and IV (They were numbered with a … WebAnswer (1 of 5): In a right triangle the cos Theta is the side adjacent to the angle (4) divided by the hypotenuse ( side opposite right angle or 5) so you have 4/5 or .80. On your calculator use the arccos button or hit second then cos and input .80 and you will get the angle, in this case 36.87... roberts family go fund me
Find sin theta given a point calculator Math Questions
Webcos θ ≈ 1 at about 0.1408 radians (8.07°) tan θ ≈ θ at about 0.1730 radians (9.91°) sin θ ≈ θ at about 0.2441 radians (13.99°) cos θ ≈ 1 − θ 2 / 2 at about 0.6620 radians (37.93°) Angle sum and difference. The angle addition and subtraction theorems reduce to the following when one of the angles is small (β ≈ 0): WebFind the possible values of sin θ and tan θ, given that cos θ = 3 / 5 and 0 ≤ θ ≤ π / 2. Here is my working out: Using a right hand triangle: cos θ = a / c cos θ = 3 / 5 a 2 = b 2 + c 2 5 2 = 3 2 + b 2 Therefore b = + 4 or − 4. Compute the values of b and c to find sin θ sin θ = b / c = 4 / 5 tan θ = sin / cos = ( 3 / 5) / ( 4 / 5) tan θ = 4 / 5. WebGiven cos θ = 4 5 Now, we have to find all the other trigonometric ratios. We have the following right angle triangle. From the above figure, Perpendicular = Hypotenuse Base Hypotenuse 2 - Base 2 ⇒ A B = A C 2 - B C 2 ⇒ A B = 5 - 4 2 => AB = 3 Therefore sin θ = A B B C = 3 5 cos e c θ = A C A B = 5 3 sec θ = A C B C = 5 4 ` tan θ = A B B C = 3 4 roberts family farm meade county ky